Q.What is the maximum number of characters (7 bits + parity) that can be transmitted in a second on a 19.2 kbps line? This asynchronous transmission requires 1 start bit and 1 stop bit.
Correct answer: 1920
Explanation
In asynchronous transmission mode, start bit and stop bit is always required whereas in asynchronous mode these bits are not required. So for this connection total number of bits in a character = 7 data bits + 1 parity bit + 1 start bit + 1 stop bit = 10 bits Bandwidth = 19.2 kbps number of characters transmitted in 1 second = (19.2 * 1000)/ 10 = 1920.
In asynchronous transmission mode, start bit and stop bit is always required whereas in asynchronous mode these bits are not required. So for this connection total number of bits in a character = 7 data bits + 1 parity bit + 1 start bit + 1 stop bit = 10 bits Bandwidth = 19.2 kbps number of characters transmitted in 1 second = (19.2 * 1000)/ 10 = 1920.